Hardy-weinberg Problems Lab 8 Answers AP Bio Lab 8 Hardy Weinberg Problem Number 6?

AP Bio Lab 8 Hardy Weinberg Problem number 6? - hardy-weinberg problems lab 8 answers

I keep getting different answers from all in this issue! So please someone help 100% sure I am out!


For some people, takes the dominant expression of a particular attribute 91% of the time. What is the frequency of the dominant allele?

2 comments:

N E said...

If the phenotype is the result of a single gene with two alleles, designated A and then the dominant phenotype results from both heterozygous and homozygous dominant AA, AA. In addition, the results of the recessive phenotype AA homozygous recessive. Since the dominant phenotype occurs 91% of the time, then one can conclude that the recessive phenotype 9% of the time (100% - 91% = 9% occurs). Therefore, the frequency of the recessive phenotype of 9% or 0.09. If we take the allele frequency p and q the frequency of the dominant allele, then there are only two alleles, the sum of the frequencies of alleles should be a:

p + q = 1

If you square both sides:

p + q = 1
(p + q) ^ 2 = 1 ^ 2
(p + q) ^ 2 = 1
p ^ 2 + 2PQ + Q ^ 2 = 1

where p ^ 2 is the dominant frequency of homozygotes is the frequency of heterozygotes is 2pq, and q ^ 2 is the frequency of homozygous recessive alleles, then:

q ^ 2 = 0.09
q = 0.3

Because:

p + q = 1

then

p = 1 - q \\ \\ \\ \\ \\ \\ \\ \\ u0026lt;br> P = 1 - 0.3 = 0.7

Therefore, the frequency of the dominant allele is 0.7

You can view the math:

p ^ 2 = 0.7 x 0.7 = 0.49
2pq = 2 x 0.7 x 0.3 = 0.42

The frequency of the dominant phenotype is the sum of the frequencies of homozygous and heterozygous dominant

p ^ 2 + 2PQ = 0.49 + 0.42 = 0.91

and this coincides with 91% occurring in the original question, if it confirms that the frequency of the dominant allele is 0.7

jnegron1... said...

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